WebA certain processor uses a fully associative cache of size 16 kB, The cache block size is 16 bytes. Assume that the main memory is byte addressable and uses a 32-bit address. How many bits are required for the Tag and the Index fields respectively in the addresses generated by the processor? WebGATE 2024 ECE Bits & Bytes (1116 Practice Questions With Solutions) Volume 2 Paperback 36 ratings See all formats and editions Paperback — Returns Policy Secure transaction Print length 358 pages Language English ISBN-10 1645970957 ISBN-13 978-1645970958 See all details Customers who viewed this item also viewed Page 1 of 2
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WebGATE CSE 2024 MCQ (Single Correct Answer) + 2 - 0.67 A computer system with a word length of 32 bits has a 16 MB byte-addressable main memory and a 64 KB, 4-way set associative cache memory with a block size of 256 bytes. Consider the following four physical addresses represented in hexadecimal notation. WebA sender uses the Stop-and-Wait ARQ protocol for reliable transmission of frames. Frames are of size 1000 bytes and the transmission rate at the sender is 80 Kbps (1Kbps = 1000 bits/second). Size of an acknowledgment is 100 bytes and the transmission rate at the receiver is 8 Kbps. The one-way propagation delay is 100 milliseconds. flanken cut short ribs recipe
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WebSep 17, 2024 · 8 bits = 1 byte. 1,024 bytes = 1 kilobyte. 1,024 kilobytes = 1 megabyte. 1,024 megabytes = 1 gigabyte. 1,024 gigabytes = 1 terabyte. As an example, to convert … http://www.bitsofbytes.co/logic-gates.html WebFeb 14, 2024 · Answer: (D) Explanation: Virtual address size = 32 bits Physical address size = 36 bits Physical memory size = 2^36 bytes Page frame size = 4K bytes = 2^12 bytes No. of bits for offset (or number of bits required for accessing location within a page frame) = 12. No. of bits required to access physical memory frame = 36 – 12 = 24 flanken ribs recipe instant pot